这是已经测试过的Ｃ语言程序
uchar crc8(uchar *ptr, uchar len)
{ 
  uchar  i; 
  uchar crc=0; 
  while(len--!=0)
  {
    for(i=1; i!=0; i <<= 1)
      {
        if((crc & 1) != 0) {crc >>= 1; crc ^= 0x8C;}
        else crc >>= 1;
        if((*ptr & i) != 0) crc ^= 0x8C;
      }
    ptr++;
    } 
  return(crc);
} 
这是我根据他编的ＶＢ程序，就是老发送０，不知道这个ＣＲＣ原理，哪位高手可以讲一下？
    '*************************************************************
    '**
    '**    CRC8校验程序
    '**
    '*************************************************************/
    Public Function CRC8(ByRef BufferAddress() As Byte, ByVal Length As Integer) As Byte
        Dim BitShiftControl As Integer, CRC As Long, index As Long
        Dim CRC8_CONSTANT As Byte = &H8C
        BitShiftControl = 0
        CRC = 0
        index = 0
        Do While (Length <> 0)
            BitShiftControl = &H1
            Do Until BitShiftControl = 0
                If (CRC And &H1) <> 0 Then
                    CRC = (CRC \ 2) And &HFF
                    CRC = (CRC Xor CRC8_CONSTANT) And &HFF
                Else
                    CRC = (CRC \ 2) And &HFF
                End If
                If (BufferAddress(index) And BitShiftControl) <> 0 Then CRC = CRC Xor CRC8_CONSTANT
                BitShiftControl = BitShiftControl * 2
                If BitShiftControl & &H100 Then
                    BitShiftControl = 0
                End If
            Loop
            index = index + 1
            Length = Length - 1
        Loop
        CRC8 = CRC And &HFF
    End Function

把算法搞清楚自己写个吧

用不用的上也帮顶一下

正所谓：“一马奔腾，射雕引弓，天

文笔老辣尖刻，读来酣畅淋漓，强贴，马克一下！

共同发展！学习才会进步，谢了

不行你就把c的函数编成连接库然后vb里调用呗，这个方法好，c效率高

lz，你现在已经不是为自己活下去了

呵呵，用查表实现的CRC8循环冗余校验程序，跟上面的C语言是一样的效果，程序如下
'*********************************************************'
    'CRC8循环冗余校验
    '*********************************************************'
    Private Function GetCRC8(ByVal Index As Byte) As Byte
        GetCRC8 = Choose(Index + 1, _
        &H0, &H5E, &HBC, &HE2, &H61, &H3F, &HDD, &H83, &HC2, &H9C, &H7E, &H20, &HA3, &HFD, &H1F, &H41, _
        &H9D, &HC3, &H21, &H7F, &HFC, &HA2, &H40, &H1E, &H5F, &H1, &HE3, &HBD, &H3E, &H60, &H82, &HDC, _
        &H23, &H7D, &H9F, &HC1, &H42, &H1C, &HFE, &HA0, &HE1, &HBF, &H5D, &H3, &H80, &HDE, &H3C, &H62, _
        &HBE, &HE0, &H2, &H5C, &HDF, &H81, &H63, &H3D, &H7C, &H22, &HC0, &H9E, &H1D, &H43, &HA1, &HFF, _
        &H46, &H18, &HFA, &HA4, &H27, &H79, &H9B, &HC5, &H84, &HDA, &H38, &H66, &HE5, &HBB, &H59, &H7, _
        &HDB, &H85, &H67, &H39, &HBA, &HE4, &H6, &H58, &H19, &H47, &HA5, &HFB, &H78, &H26, &HC4, &H9A, _
        &H65, &H3B, &HD9, &H87, &H4, &H5A, &HB8, &HE6, &HA7, &HF9, &H1B, &H45, &HC6, &H98, &H7A, &H24, _
        &HF8, &HA6, &H44, &H1A, &H99, &HC7, &H25, &H7B, &H3A, &H64, &H86, &HD8, &H5B, &H5, &HE7, &HB9, _
        &H8C, &HD2, &H30, &H6E, &HED, &HB3, &H51, &HF, &H4E, &H10, &HF2, &HAC, &H2F, &H71, &H93, &HCD, _
        &H11, &H4F, &HAD, &HF3, &H70, &H2E, &HCC, &H92, &HD3, &H8D, &H6F, &H31, &HB2, &HEC, &HE, &H50, _
        &HAF, &HF1, &H13, &H4D, &HCE, &H90, &H72, &H2C, &H6D, &H33, &HD1, &H8F, &HC, &H52, &HB0, &HEE, _
        &H32, &H6C, &H8E, &HD0, &H53, &HD, &HEF, &HB1, &HF0, &HAE, &H4C, &H12, &H91, &HCF, &H2D, &H73, _
        &HCA, &H94, &H76, &H28, &HAB, &HF5, &H17, &H49, &H8, &H56, &HB4, &HEA, &H69, &H37, &HD5, &H8B, _
        &H57, &H9, &HEB, &HB5, &H36, &H68, &H8A, &HD4, &H95, &HCB, &H29, &H77, &HF4, &HAA, &H48, &H16, _
        &HE9, &HB7, &H55, &HB, &H88, &HD6, &H34, &H6A, &H2B, &H75, &H97, &HC9, &H4A, &H14, &HF6, &HA8, _
        &H74, &H2A, &HC8, &H96, &H15, &H4B, &HA9, &HF7, &HB6, &HE8, &HA, &H54, &HD7, &H89, &H6B, &H35)
    End Function
    '*********************************************************'
    'CRC8循环冗余校验
    '*********************************************************'
    Public Function CRC8(ByVal bData() As Byte) As Byte
        Dim CRC_Temp As Byte
        Dim CRC_Index As Byte
        Dim i As Long
        CRC_Temp = 0
        For i = LBound(bData) To UBound(bData)
            CRC_Index = CRC_Temp Xor bData(i)
            CRC_Temp = GetCRC8(CRC_Index)
        Next
        CRC8 = CRC_Temp
    End Function